Easy solution of RS Aggarwal Class 8 Chapter 2 Exercise 2B Solution (Exponents)
Go RS Aggarwal Class 8 Solution
(1) Write each of the following numbers in standard form:
(i) 57.36
⇒5.736× 101
(ii) 3500000
⇒3.5× 106
(iii) 273000
⇒2.73× 105
(iv) 168000000
⇒1.68× 108
(v) 4630000000000
⇒4.63× 1012
(vi) 345×105
⇒3.45× 107
(2) write each of the following numbers in usual form:
(i) 3.74× 105
⇒374000
(ii) 6.912× 108
=691200000
(iii) 4.1253× 107
=41253000
(iv) 2.5× 104
=25000
(v) 5.17× 104
=5170000
(vi) 1.679× 109
=1679000000
(3)
(i) The height of Mount Everest is 8848 m. Write it in standard form.
=8.848× 103 m
(ii) The speed of light is 300000000 m/sec. Express it in standard form.
=3× 108 m/sec.
(iii) The distance from the earth to the sun is 149600000000 m. Write it in standard form.
=1.496× 1011 m
(4) Mass of earth is (5.97× 1024)kg. and Mass of moon is (7.35× 1022) Kg. What is the total mass of the two?
Mass of earth is (5.97× 1024 )=597× 1022 kg
And Mass of moon = (7.35× 1022)
Now sum = (597+7.35)× 1022 kg =604× 1022 kg
(5) Write each of the following numbers in standard form:
(i) 0.0006
=6× 10-4
(ii) 0.00000083
=8.3× 10-7
(iii) 0.0000000534
=5.34× 10-8
(iv)0.0027
=2.7× 10-3
(v) 0.00000165
=1.65× 10-6
(vi) 0.00000000689
=6.89× 10-9
(6) (i) 1 micron =1/1000000 m . Express it in standard form.
=1/1000000 m=1× 10-6 m
(ii) Size of bacteria = 0.0000004 m .Express it in standard form.
=0.0000004 m=4× 107m
(iii) Thickness of a paper = 0.03 mm. Express it in standard form.
0.03 mm=3× 10-2 mm
RS Aggarwal Class 8 Maths Solution Exercise 2A
RS Aggarwal Class 8 Maths Solution Exercise 2C
(7) Write each of the following numbers in usual form:
(i) 2.06× 10-5
=0.0000206
(ii) 5× 10-7
=0.0000005
(iii) 6.82× 10-6
=0.00000682
(iv) 5.673× 10-4
=0.0005673
(v) 1.8× 10-2
=0.018
(vi) 4.129× 10-3
=0.004129